Dyno Report Query
#1 _draglc_
Posted 19 December 2005 - 06:10 PM
got my newish engine dynoed last week.
Its a 202 + 40thou, flat top pistons, blue rods, nitrous cam .238 & .248 @ .50, 1.6 inlet & 1.5 outlet ratio roller rockers, 186 YT head big valves etc, straight cut gears, triple 1.75 HIF SU's, elec dizzy and splitfire 8.8mm leads.. etc u get the idea.
anyway it made 151hp at 5500rpm, and it also says it made 780nm at 60kph.
This is what i dont get. 780mn is approx 575.22ft-lb. In the latest street machine, on page 92 theres an article on an elcamino that has 450hp and 470ft-lb of torque. What i dont understand is how my 151hp 202 can have 105.22ft-lb more torque than a 450hp blown 350 chev????
Cheers,
A1
#2 _devilsadvocate_
Posted 19 December 2005 - 07:51 PM
Or sounds like it was a full throttle exercise down in second gear only?
Possibly it is just the torque measured on the rollers of the dyno and hasnt been recalculated according to your engine rpm.
Edited by devilsadvocate, 19 December 2005 - 07:54 PM.
#3 _Terrible One_
Posted 19 December 2005 - 07:55 PM
#4 _devilsadvocate_
Posted 19 December 2005 - 08:12 PM
if you look up tractive effort, Ill think youll see it concurs with my explanation about the forces measured on the rollers/wheels and how it can be recalculated according to rpm and gearing/wheel size etc.No, it's 780nM of tractive effort. It's common for fairly quick cars to have upwards of 1000nM of tractive effort.
#5 _Terrible One_
Posted 19 December 2005 - 08:46 PM
#6 _draglc_
Posted 19 December 2005 - 08:47 PM
ill put a pic up of the sheets when i can.
A1
#7 _devilsadvocate_
Posted 19 December 2005 - 11:16 PM
Draglc: Im not particularly fond of the term 'tractive effort'; effort implies a unit of force not the quantity of torque. However, unless the dyno operator keys in such things as your wheel size, gear ratios etc, then the torque at the crankshaft cant be quoted accurately, the figure from the rollers is obviously a real figure and can be used for comparison purposes when tuning the car etc. I hope it wasnt written as 780nm? that would be nanometres! N for newtons, m for metres.(Nm)
Was your dyno run done in 2nd gear?
#8 _draglc_
Posted 20 December 2005 - 06:54 AM
A1
#9
Posted 20 December 2005 - 10:08 AM
This is because the dyno figures torque from road speed, not engine speed.
#10 _Yella SLuR_
Posted 20 December 2005 - 10:46 AM
Struggler, so how do you work it back to actual engine torque? Is that possible? Mine pushed out 1200 lb.ft. of tractive power through 15" rims with 265x60 profile treads through a 3:08 diff in top gear.
#11 _Yella SLuR_
Posted 20 December 2005 - 10:53 AM
Without hijacking too much, Struggler, the bumps and dips concern me, what is that telling me? Will have to get back into my car one day (damn castle!!!).
Other cars on the day pushed around 800lb fairly consistently. Why was mine so high?
Edited by Yella SLuR, 20 December 2005 - 10:55 AM.
#12 _draglc_
Posted 20 December 2005 - 12:40 PM
#13 _dansedgli_
Posted 20 December 2005 - 01:56 PM
The last car I owned that I put on a dyno that read NM pulled 1150nm. It had 202rwkw.
#14 _devilsadvocate_
Posted 20 December 2005 - 03:47 PM
Otherwise torque at the crankshaft can be calculated by:
torque(Nm) = power(kW) x 9554/rpm
so if 100kw at 3000rpm , torque = 100x9554/3000= 318Nm
or if using imperial
torque(lbft) = power(hp) x 5256/rpm
#15 _devilsadvocate_
Posted 20 December 2005 - 10:21 PM
However looking at yella's data, it doesnt appear to be the case.
Calculating torque from yella's figures at 100kmh, hp =120, rpm = 2335.6(using his wheel and diff data) Torque(using the formula in my last post) works out to be 269lbft.
Using the tractive effort value of 700lbft at the same speed, divide by diff ratio and multiply by radius of wheel in feet. 700/3.08 x (13.8(tyre radius inches)/12)=261lbft. Very comparable.
1200lbft translates to 448lbft at flywheel.
If we do the same for your figs draglc: 780/3.08 x (.56/2)= 70.9Nm, which just doesnt seem large enough for max torque on your vehicle, you could ask them how they reckon they might get the calc looking right....
#16 _draglc_
Posted 21 December 2005 - 10:04 PM
Hopefully i can understand it, and remember it long enough to tell yas all about it!
A1
#17 _thebigsy_
Posted 30 December 2005 - 05:15 PM
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